lets see...
hmmm...
type numbers not words...
ok already get on with it...
0 = 4x^2 + 12x - 2
2 + 0 = 4x^2 +12x - 2 + 2
2 = 4x^2 + 12x
2 - 12x = 4x^2 + 12x - 12x
hmmm...
I think this is why the quadratic equation was invented...FOIL...oh yeah I gotta continue with that up there...
(2 - 12x)/4 = x^2
hmmm....
factor maybe...
2(2x^2 + 6x - 1) ok...I think that's the first step actually duh...the only number x can be is 0 because the equation is 0, if 0 were y then you would have to solve this way then use the QE, then set y to 0 or something. I'm really not a math major, but this was enough refresher to keep the saw sharp. Nah, let's solve it.
y = 2(2x^2 + 6x - 1)

x = 0.1583123
x = -3.1583122
hmmm, now that we know x we gotta set...hmm...solve for y...ok, I'm using an online graphing calculator for this part...
y = -0.0000012626748
y = -0.0000025893246
these are the solutions to something, just not what I was looking for, oh well TBC on another day... I think the correct way is to pull out the 2 and factor...something like y = 2(2x + 1)(x - 1)...and since it can't be easily factored back to the quadratic formula...I want to find the Vertex...and according to the graphing calculator I'm looking for y = -11...
So that's the solution, punch it into a graphing calculator, and read the graph...hahahahahaha
No, do not use the online Desmos Graphing Calculator, it doesn't know what it's talking about (or I'm entering the function wrong), but I"m fairly certain it doesn't know what it's talking about...
To find the vertex of
0 = 4x^2 + 12x - 2
simply enter x=0, answer y = -2
The vertex is at -2 duh.
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